Showing posts with label algebraic expression. Show all posts
Showing posts with label algebraic expression. Show all posts

Thursday, September 3, 2009

Solving System of Equations

In mathematics, a system of linear equations is a collection of linear equations involving the same set of variables. For example,
\begin{alignat}{7} 3x &&\; + \;&& 2y             &&\; - \;&& z  &&\; = \;&& 1 & \\ 2x &&\; - \;&& 2y             &&\; + \;&& 4z &&\; = \;&& -2 & \\ -x &&\; + \;&& \tfrac{1}{2} y &&\; - \;&& z  &&\; = \;&& 0 & \end{alignat}
is a system of three equations in the three variables x, y, z\,\!. A solution to a linear system is an assignment of numbers to the variables such that all the equations are simultaneously satisfied. A solution to the system above is given by
\begin{alignat}{2} x & = & 1 \\ y & = & -2 \\ z & = & -2 \end{alignat}
since it makes all three equations valid.so this is specially for linear equations in two variables or more than two variables.

In mathematics, the theory of linear systems is a branch of linear algebra, a subject which is fundamental to modern mathematics. Computational algorithms for finding the solutions are an important part of numerical linear algebra, and such methods play a prominent role in engineering, physics, chemistry, computer science, and economics. A system of non-linear equations can often be approximated by a linear system (see linearization), a helpful technique when making a mathematical model or computer simulation of a relatively complex system.This is how linear equations explained ,let's see a example on this now from linear algebra tutoring online.
Question:-

Solve the system of equations

8x-z=4

y+z=5

11x+y=15

Answer:-

8x-z=4 ----- eq1

y+z=5 ---- eq2

11x+y=15 -----eq3

add eq1 and eq2

we get 8x+y=9 ----- eq4

subtract eq4 from eq3

11x+y=15
-8x+y=9
-----------
3x = 6

x =2

putting this value in eq1

8x-z =4

16-z=4

z=12

putting this value in eq2

y+z = 5

y = -7

so x=2 , y= -7 and z=12

Wednesday, May 27, 2009

Converting an algebraic expression into dependent variables of a single variable

Here is an algebra question where in a given algebraic expression like terms are on one side and unlike term on another side, this problem is all about making into different subject.

Topic : Making into different subject

This example would clearly explain what making into different subject exactly mean.

Problem : Let f = uv / (u + v) Make “v” as the subject

Solution :


f = uv / (u + v)
Multiplying by (u + v) on either sides of the equation
f (u + v) = uv
fu + fv = uv
Subtract fv on both the sides
fu = uv – fv
fu = v(u – f)
fu / (u – f) = v

Hope the meaning on coverting to different subject is well understood by above example, for more algebra questions like this contact algebra help.