Showing posts with label algebra help. Show all posts
Showing posts with label algebra help. Show all posts

Thursday, September 3, 2009

Solving System of Equations

In mathematics, a system of linear equations is a collection of linear equations involving the same set of variables. For example,
\begin{alignat}{7} 3x &&\; + \;&& 2y             &&\; - \;&& z  &&\; = \;&& 1 & \\ 2x &&\; - \;&& 2y             &&\; + \;&& 4z &&\; = \;&& -2 & \\ -x &&\; + \;&& \tfrac{1}{2} y &&\; - \;&& z  &&\; = \;&& 0 & \end{alignat}
is a system of three equations in the three variables x, y, z\,\!. A solution to a linear system is an assignment of numbers to the variables such that all the equations are simultaneously satisfied. A solution to the system above is given by
\begin{alignat}{2} x & = & 1 \\ y & = & -2 \\ z & = & -2 \end{alignat}
since it makes all three equations valid.so this is specially for linear equations in two variables or more than two variables.

In mathematics, the theory of linear systems is a branch of linear algebra, a subject which is fundamental to modern mathematics. Computational algorithms for finding the solutions are an important part of numerical linear algebra, and such methods play a prominent role in engineering, physics, chemistry, computer science, and economics. A system of non-linear equations can often be approximated by a linear system (see linearization), a helpful technique when making a mathematical model or computer simulation of a relatively complex system.This is how linear equations explained ,let's see a example on this now from linear algebra tutoring online.
Question:-

Solve the system of equations

8x-z=4

y+z=5

11x+y=15

Answer:-

8x-z=4 ----- eq1

y+z=5 ---- eq2

11x+y=15 -----eq3

add eq1 and eq2

we get 8x+y=9 ----- eq4

subtract eq4 from eq3

11x+y=15
-8x+y=9
-----------
3x = 6

x =2

putting this value in eq1

8x-z =4

16-z=4

z=12

putting this value in eq2

y+z = 5

y = -7

so x=2 , y= -7 and z=12

Wednesday, August 12, 2009

Commutative and Distributive Number Properties

Number properties are
Associative property applies to both addition and multiplication: a+(b+c)=(a+b)+c, a*(b*c)=(a*b)*c.
Distributive property ties addition and multiplication together. Distributive property can be written as: a*(b+c) = a*b + a*c.
Commutative property means that operands can switch places: a+b=b+a, a*b=b*a.

For Example:
Question 1 :- Distributive PropertyThe property demonstrated in the equation -(3n - 5) = -3n + 5 is:
a. associative b. commutative c. distributive d. Neither side of the equation is equal to the other.
Answer:
-1(3n-5) = -3n+5
(-1) (3n) + (-1) (-5)
= -3n+5 (Distributive Property)

Question 2 :- Associative Property
property demonstrated in the equation (5 + n) - 2 = 5 + (n - 2) is:
Answer:
(5+n)-2 = 5+(n-2)
Here the grouping that is the parentheses has changed.so it a (Associative Property)

Question 3 :- Commutative Property
property is this one 7 - 4 + 2 = 7 + 2 – 4
Answer:
7 - 4 + 2 . 7 + 2 - 4
Here the order - 4 + 2 has become 2 + - 4. So it is a (Commutative Property)

Monday, June 29, 2009

problem on elimination methos

Topic:- Elimination method

When we are solving equations in algebra ,We can add or subtract the equations ,So that
We can simplify the equations , This is called elimination method

Here we have a simple example to show you ,how this methos works.

This algebra help shows ,how to solve equations as well.

Question :

x+y = 7 and x-y = 9

Solve for 'x',By using elimination method.

Answer:-

Let's add both the equations

      x + y = 7
      x - y = 9
 ------------------
        2x = 16


Divide with 2 on both sides


       2x     16
      ---- = -----
       2       2


        x = 8


So 8 is the answer


For more help ,please reply me .

Wednesday, May 27, 2009

Converting an algebraic expression into dependent variables of a single variable

Here is an algebra question where in a given algebraic expression like terms are on one side and unlike term on another side, this problem is all about making into different subject.

Topic : Making into different subject

This example would clearly explain what making into different subject exactly mean.

Problem : Let f = uv / (u + v) Make “v” as the subject

Solution :


f = uv / (u + v)
Multiplying by (u + v) on either sides of the equation
f (u + v) = uv
fu + fv = uv
Subtract fv on both the sides
fu = uv – fv
fu = v(u – f)
fu / (u – f) = v

Hope the meaning on coverting to different subject is well understood by above example, for more algebra questions like this contact algebra help.